The apparent weight of a body wholly immersed in water is 32N and its weight in air is 96N. Calculate the volume of the body. (Density of water = 1000kgm-3, g = 10ms\(^{-2}\))
8.9 x 10-3m3
6.4 x 10-3m3
3.2 x 10-3m3
3.0 x 10-3m3
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Upthrust = 96 - 32 = 64N
force= mass(m) x acceleration due to gravity(a)
mass(m) =64/10 = 6.4kg
volume = mass/Density =6.4/1000
= 6.4 x 10-3m3
upthrust = weight on air - weight in water
this is 96 - 32 = 64
now upthrust is also = density * volume * acceleration due to gravity.
so 64 = 1000* 10 * volume
and volume is 64/ 10,000
= 0.0064 ie 6.4 * 10 -3
Find upthrust=96-32=64
Upthrust=density ×volume×gravity
64=1000×V×10
V=64/10000
V=0.0064m^3
In standard form
=6.4×10^-3m^3
It indicates that my answer is wrong, it gives it's own answer but no solvings.
