A radioactive nuclide of proton number X emits a \(\beta\)-particle to form a new nuclide to proton number Y. The correct equation relating X and Y is
X = Y - 1
X = Y + 1
X = 1 - Y
X = \(\frac{1}{y}\)
X = Y
Explanation
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Discussions (17)
beta emits particle that cause rise in proton number, the answer is A x=y-1 not B.
(A) is d correct option bcos beta emission results to rise in proton number.There4 Y>X
The answer is Undisputably, A.
Beta particle adds 1 to the proton number, as such, Y= X +1. Therefore, with respect to X, we will have X= Y - 1. Thanks 
When a radioactive nuclide emits a β-particle (beta-minus decay, ), a neutron in the nucleus is converted into a proton. As a result:
The proton number increases by 1 (since a neutron becomes a proton).
The nucleon number (mass number) remains the same because a neutron is lost, but a proton is gained.
Thus, if the original nuclide has a proton number X, the new nuclide will have a proton number Y = X + 1.
The correct equation relating X and Y is:
Y = X + 1
So the answer given by myschool is Correct 
Hi
my school
pls the ans is A
we know from ur explanation that proton no increases
but the option u chose proton no is decreased cos Y is the final product of the decay and Y must be equal to X+1 .... and that is found in option A when reversed
beta emits particle that cause rise in proton number, the answer is B x=y-1 not A.
