The diagram below illustrates an a.c.source of 50V(r.m.s.), \(\frac{100}{\pi}\)Hz connected in series with an inductor of inductor of inductance L and a resistor of resistance R. The current in the circuit is 2A and the p.d across L and R are 30V and 40V respectively. Calculate the average power dissipated in the circuit

MaraeX

9 years ago

please this explanation is not clear

it almost doesnt resemble d question

Badewole34

1 year ago

power = i²R

in the Resistor, there is a 40Volts across it,. then you calculate for the resistance R which is

V=IR
R=V/I
R=40/2
R=20Ω

then you calculate for your power

Bohloowahteefeh

1 year ago

This doesn't correlate with the question, please we need video

Purity252

2 months ago

where does the 30volts and 50volts go to?