A cell of e.m.f. 1.5v is connected in series with a resistor of 3\(\Omega\). A high resistance voltmeter connected across the cell registers only 0.9v. Calculate the internal resistance of the cell

shegzywurld

4 years ago

E= IR+It
V= IR
0.9=3I
I= 0.9/3
I= 0.3
Since, E= IR+Ir
1.5= 0.9 + 0.3r
1.5-0.9= 0.3r
0.6=0.3r
r= 0.6/0.3
r= 2

Temo95

11 months ago

Cheat Formula 🤌 V/E = R/R+r
v= 0.9
E=1.5
R =3
r =0.9
0.9/1.5 =3/3+r
0.9(3+r) = 1.5*3
2.7 + 0.9r = 4.5
0.9r = 4.5-2.7
r =1.8/0.9
r = 2ohms

Michaelm2g

10 years ago

Am sorry. U guys r wrong... D ans is D....... E=V+ir......

oolufayo

5 years ago

Sanusi, it was probably a mistake, because the final answer is still correct.

Theoretically

5 years ago

How is 0.9/3=3

mercy olalemi

9 years ago

k