An electromagnetic wave of frequency 5.0 x 1014Hz, is incident on the surface of water of refractive index \(\frac{4}{3}\). Taking the speed of the wave in air as 3.0 x 108ms-1, calculate the wavelength of the wave in water.
a
2.2 x 10-6m
b
1.7 x 10-7m
c
8.0 x 10-7m
d
6.0 x 10-7m
e
4.5 x 10-7m
Explanation
Correct Option
eVideo Explanation
No video available
Post your Contribution
Share:
Discussions (5)
Saihim442
8 years ago
Velocity = frequency * wavelength... ₹ wavelength=velocity/frequency...: 3.0/5.0^8-14=0.6= 6.0*10^-7 .... Therefore: since the wave is in water and the refractive index is given as 4/3=1.33. Then 0.6/1.33=0.451...4.5*10^-7m (E)
dimah
10 years ago
velocity = frequency × wavelength
wavelength = velocity ÷ wavelength
wavelength = (3× 10^8) ÷ (5× 10^14)
wavelength = 6.0 × 10^7.
ans = C
