Physics
WAEC 1998
the shortest length of the air column in a resonance tube at resonance is 0.12m and the next resonance length is 0.37m. calculate the frequency of vibration given that the speed of sound in air is 340m
-1
-
A.
1360Hz
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B.
694Hz
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C.
680Hz
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D.
34Hz
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E.
340Hz
Correct Answer: Option C
Explanation
f = \(\frac{v}{2(l_2 - l_1)} = \frac{340}{2(0.37 - 0.12)} = \frac{34}{0.5}\) = 680
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