An object is heated from 30ºC to 57ºC. The increases in its temperature on the Kelvin scale is

a

17k

b

27k

c

81k

d

246k

e

300k

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Explanation

Correct Option
b

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Discussions (13)

User1010
2 years ago

27k is very wrong.
The correct answer is 300k
57°c-30°c=(27+273)=300k

RYUK
4 years ago

30°C+273=303K
57°C+273=330K
∆T=330K - 303K =27K
∆T=27K

Sammy3004
4 years ago

Yo, the answer is supposed to be 27K, innit?😒

Fatimah234
2 years ago

27k is wrong

Ayomi424
4 years ago

The answer is 27kelvin😒

hakmuz
1 year ago

An object is heated from 30oC to 57oC. The increases in its temperature on the kelvin scale is

A. 17k
B. 27k
C. 81k
D. 246k
E. 300k
ChatGPT
To find the increase in temperature on the Kelvin scale, you can simply use the temperature difference in Celsius, because a change of 1°C is equivalent to a change of 1 K.

Given:

Initial temperature:
3
0

C
30

C
Final temperature:
5
7

C
57

C
The increase in temperature in Celsius is:

5
7

C

3
0

C
=
2
7

C
57

C−30

C=27

C

Since a temperature change of 27°C is equivalent to a temperature change of 27 K, the increase in temperature on the Kelvin scale is:

B. 27 K


2/2

Are you sure?
ChatGPT
Yes, I am sure. The increase in temperature in Celsius is directly equivalent to the increase in temperature in Kelvin.

The calculation is:

Initial temperature:
3
0

C
30

C
Final temperature:
5
7

C
57

C
The temperature change in Celsius is:

5
7

C

3
0

C
=
2
7

C
57

C−30

C=27

C

Since 1°C change is equivalent to a 1 K change, the temperature increase on the Kelvin scale is also 27 K.

So, the correct answer is B. 27 K.

Olanrewaju777
4 years ago

27 is legit

Newton2i
2 years ago

the ans is 27k all this quack keep on working something 😂🤣 else even without working just remove 57 from 30 and it we give you 27 C
since 1celcius is the same as 1kelvin on the kelvin scale so 27c = 27k

Newton2i
2 years ago

57°C - 30°C = (27 + 273)
= 300k i think here it you are right increase in temperature

Etugo
10 years ago

The right answer is 27K

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