An object is heated from 30ºC to 57ºC. The increases in its temperature on the Kelvin scale is
17k
27k
81k
246k
300k
Explanation
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An object is heated from 30oC to 57oC. The increases in its temperature on the kelvin scale is
A. 17k
B. 27k
C. 81k
D. 246k
E. 300k
ChatGPT
To find the increase in temperature on the Kelvin scale, you can simply use the temperature difference in Celsius, because a change of 1°C is equivalent to a change of 1 K.
Given:
Initial temperature:
3
0
∘
C
30
∘
C
Final temperature:
5
7
∘
C
57
∘
C
The increase in temperature in Celsius is:
5
7
∘
C
−
3
0
∘
C
=
2
7
∘
C
57
∘
C−30
∘
C=27
∘
C
Since a temperature change of 27°C is equivalent to a temperature change of 27 K, the increase in temperature on the Kelvin scale is:
B. 27 K
2/2
Are you sure?
ChatGPT
Yes, I am sure. The increase in temperature in Celsius is directly equivalent to the increase in temperature in Kelvin.
The calculation is:
Initial temperature:
3
0
∘
C
30
∘
C
Final temperature:
5
7
∘
C
57
∘
C
The temperature change in Celsius is:
5
7
∘
C
−
3
0
∘
C
=
2
7
∘
C
57
∘
C−30
∘
C=27
∘
C
Since 1°C change is equivalent to a 1 K change, the temperature increase on the Kelvin scale is also 27 K.
So, the correct answer is B. 27 K.

the ans is 27k all this quack keep on working something 
else even without working just remove 57 from 30 and it we give you 27 C
since 1celcius is the same as 1kelvin on the kelvin scale so 27c = 27k

57°C - 30°C = (27 + 273)
= 300k i think here it you are right increase in temperature





