A ball of mass 5.0kg hits a smooth vertical wall normally with a speed of 2m-1 and rebounds with the same speed. Determine the impulse experienced by the ball
Using: \(\text{Impulse} = \Delta \text{Momentum} = m(v - u)\)
Initial Momentum: \(5\text{ kg} \times 2\text{ m/s} = +10\text{ kg m/s}\)
Final Momentum: \(5\text{ kg} \times (-2\text{ m/s}) = -10\text{ kg m/s}\)
Change: \(-10 - 10 = -20\text{ kg m/s}\)
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