A ball of mass 5.0kg hits a smooth vertical wall normally with a speed of 2m-1 and rebounds with the same speed. Determine the impulse experienced by the ball

biophychem

9 years ago

Here is an explanation:

the rebound velocity will b negetive=-2

ft=impulse=m(v-u)=5(2-(-2))=5(2+2)=5(4)=20....it a piece of cake.cheek it out

Kadima

9 years ago

Here is an explanation:

Poet:Given data:mass of d body=5kg;speed(v)=2m/s....at a re-bounce,d velocity(u)=-2m/s.....recall:momentum=mass*velocity...Force experienced to create d shock=impulse/time of which if related to force=change in momentum/time..I.e F=(mv-mu)/t..........Impulse=mv-mu....m(v-u).....5(2-(-2)).....Impulse=5(2+2)=5(4).....Impulse=20Ns...thanks

DevChris

1 month ago

ai explanation parsing error