An object is protected with a velocity of 100m^-1 at an angle of 60^o to the vertical. Calculate the time taken by the object to reach the highest point (Take g as 10ms^-2

chimadaniel

6 years ago

Wrong
Correct answer is A 5sec

Mayorlizz

1 year ago

t=usin@/g
@=90-60=30
t=100*sin 30/10
t=100*0.5/10
t=50/10
t=5secs
option A

cxnserr_szn

2 years ago

Can someone help out with the workings?

Chizzyhelen

2 months ago

I agree with what Emmanuel said
Time taken to reach maximum height is half the time of flight

Chizzyhelen

2 months ago

The answer is not A pls check your workings

Tobscollins

10 years ago

Pls ch

Tobscollins

10 years ago

Pls check ur workings, is 2usin0/g = 2*100*0.866/10 = 20*0.866 =17.3 u jst failed me 3 times pls y

temiuel

10 years ago

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