In the circuit above R is a resistor whose resistance increases with an increase in temperature. L1 and L2 are identical lamps. If the temperature of R increases

a

L1 becomes brighter and L2 becomes dimmer

b

L1 becomes brighter and L2 does not change

c

L2 becomes dimmer and L1 does not change

d

L1 becomes dimmer and L2 does not change

e

L1 and L2 becomes brighter

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Explanation

Correct Option
e

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Discussions (14)

adesusielisha
2 years ago

hmmmm!!!šŸ˜•šŸ˜•šŸ˜•I thought d answer is C,bcos dis is parallel connection,If d resistance,R, is increasing L1 is neither bright nor dimmer,but constant.

Let's analyze the circuit:

L1 and L2 are in parallel branches.

L2 is in series with resistor R, which increases resistance as temperature increases.

L1 is alone in its branch — no resistor in series.


Now, when the temperature of R increases, the resistance of R increases, causing less current to flow through the branch with L2.

This means:

L2 gets less current, so it becomes dimmer.

More current is diverted to the L1 branch, so L1 becomes brighter.


So the correct answer is:

A. L₁ becomes brighter and Lā‚‚ becomes dimmer.

Fave.x
1 year ago

the answer is d

option A is the correct answer.

Please review

g9ifted006
1 month ago

the answer is d myschool šŸ¤ŒšŸ¼

912226930worthy
2 months ago

both my school and my school ai are both giving me wrong answers

samlaz
2 years ago

No diagram

FRANKALO
3 months ago

L1 is aparallel connection and not a series connection

FRANKALO
3 months ago

The battery keeps the voltage the same.
Please correct me if I am wrong

adoobis
8 months ago

The answer is wrong

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