A particle of charge q and mass m moving with a velocity v enters a uniform magnetic field b in the direction of the field. The force on the particle is

Tpriye

1 year ago

Soooooooooooo....The formula for the force experienced by a charged particle entering a magnetic field is qvbsinθ. Where, q is the charge of the particle, v is the velocity of the particle and b is the magnetic strength of the field in Tesla and θ is the angle subtended from the movement of the particle to the direction of the field. In the question above, the particle moves in the direction of the field, therefore it is parallel to the field and the angle between two parallel lines (as you should know) is 0. Doing the simple math, sin (0) = 0. Multiplying anything by 0 will give you 0 so the total force experienced by that particle is, F = q × v × b × (0) = 0. Therefore, your answer is 0. It is highly important to completely and fully read the question so as to not avoid vital information like the part that said "...in the direction of the field...". Wasn't that hard was it...