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A ray of light is incident at an angle of 30º on a glass prism of...

Physics
WAEC 1991

A ray of light is incident at an angle of 30º on a glass prism of refractive index 1.5. Calculate the angle through which the ray is minimally deviated in the prism. (The medium surrounding the prism is air)

  • A. 10.5o
  • B. 19.5o
  • C. 21.1o
  • D. 38.9o
  • E. 40.5o
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Correct Answer: Option C
Explanation

n = \(\frac{sin i}{sin r}\)

sin r = \(\frac{30^o}{n}\)

sin r = \(\frac{0.5}{1.5}\)

sin r = 0.3333

r = sin\(^{-1}\)(0.333) = 19.5º

At minimum deviation, the ray passes symmetrically, so A = 2r

A = 2 x 19. 5 = 38.94

But minimum deviation = 2i - A

 = 2 x (30º) - 38.94 = 21.06º

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