Physics
WAEC 1991
A fixed mass of gas of volume 600cm
3 at a temperature of 27
oC is cooled at constant pressure to a temperature of 0
oC. What is the change in volume?
-
A.
54cm2
-
B.
273cm2
-
C.
300cm2
-
D.
546cm2
-
E.
600cm2
Correct Answer: Option A
Explanation
\(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)
T2 = 0 + 273 = 273k
V1 = 600
T1 = 27 + 273 = 300k
V2 = \(\frac{V_1T_2}{T_1}\) = 546cm
V1 - V2 = 54cm
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