A wire, 20m long is heated from a temperature of 5oC to 55oC. If the change in length is 0.020m, calculate the linear expansivity of the wire
\(\alpha = \frac{\Delta L}{L \Delta \theta} = \frac{0.020}{20 \times (55 - 5)} = 2.0 \times 10^{-5}\)
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