A ball is projected horizontally from the top of a hill with a velocity of 20m^-1. If it reaches the ground 4 seconds later, what is the height of the hill? (g = 10ms^-2)

20m

40m

80m

160m

200m

Correct Option

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1 year ago

s=1/2gt²
(10*4*4)/2
160/2=80m.

4 years ago

2 months ago

why didnt we use the 20m/s

2 years ago

Please where did we insert the 20ms-1

2 months ago

its correct🤩

4 years ago

Very wrong
U guys didn't even divide with 1/2
And shld b 40m

ceoofwahala

20th June, 2026

Chemistry

2 comments

ASSAAS

20th June, 2026

English Language

5 comments

infinitehoaxx

21st May, 2026

Computer

4 comments

A ball is projected horizontally from the top of a hill with a velocity of 20m-1. If it reaches the ground 4 seconds later, what is the height of the hill? (g = 10ms-2)