A gas at a volume of V0 in a container at pressure P0 is compressed to one-fifth of its volume. What will be its pressure if the magnitude of its original temperature T is constant?
P0/5
4P0/5
P0
5P0
Explanation
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Here is an explanation:
Using Boyle's law.
PoVo=p2×1/5Vo
PoVo=P2×Vo/5
PoVo=P2Vo/5
Cross multiply
5PoVo=P2Vo
Divide both sides by Vo
5Po=P2 i.e P2=5Po
the answer is D because according to boyle's law, pressure is inversely proportional to volume at constant temperature. the pressure decreases when the volume increases. if the volume is decreased 5 times, the pressure will increase 5 times
P0Vo=P2Vo/5 by cross multiplying u hv 5PoVo=p2Vo the divide both side by Vo u we nw hv P2=5Po
Using Boyles law formular: PoVo=PiVi
then substitute;
PoVo=Pi*I/5Vo
collecting like terms:
Pi=PoVo*5/ Vo
Divide by Vo
Pi=5Po
I prefer shortcuts especially when it has to do with jamb. The more the pressure increases, the smaller the volume gets. In other words, the lower the pressure, the higher the volume. So if the volume is decreased by 5, it means the decrease of the volume is as a result of an equal increase in pressure. I.e 5Po. D is correct
according to boyles law,volume and pressure are inversely proportioned provided temperature remains constant.therefore,since volume was reduced to 1/5 its original value,pressure will increase by 5 times it original value
