A solid weigh 10 .00 N in air, 6 N when fully immersed in water and 7 . 0 N when fully immersed in a liquid X. Calculate the relative density of the liquid, X.
R.D = \(\frac{\text{loss in weight in liquid X}}{\text{ loss in weight in water}}\)
R.D = \(\frac{(10 - 7)}{(10 - 6)}\) = \(\frac{3}{4}\)
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}