Two bodies have masses in the ratio 3:1. They experience forces which impart to them...

Two bodies have masses in the ratio 3:1. They experience forces which impart to them acceleration in the ratio 2:9 respectively. Find the ratio of forces the masses experienced.

  • A. 1 : 4
  • B. 2 : 1
  • C. 2 : 3
  • D. 2 : 5
Correct Answer: Option C
Explanation

Let the forces be F1, and F2.
F1 = m1 a1 = 3 x 2 = 6N

F2 = m2 a2 = 1 x 9 = 9N

F1 : F2 = 6:9 = 2:3

Thus ratio of forces is 2: 3


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Contributions (74)

Beloved Dom
6 years ago
Deducing d mathematical representation of Newton's 2nd law of motion,we have F=MA.Frm our quesn

M1=2,A1=3,M2=9,A2=1

Relate them 2gether:

2*3:9*1

=6:9(divide through using their possible smallest integers i.e3 ofcourse)

=2:3 ans.....c
nworu emeka
5 years ago
Anoda method is,2:1and3:9=3/2*1/9,cross divide,which is 9 divided 3, u get 3,and 2 divided 1 u get 2,which is 2:3,as answer.
Evetic22
5 years ago
Emekks tanks alot nd many of u guys 4 ur explalation ok am pleasured by it
ARRuZzABRYLE
3 years ago
we know that f=ma and we are having 2 masses and 2 accelerarions....xo we jst say f1 * m1 = f2 * m2 which is equal "6=9"...then divide both sides with 3 den we have 2:3
Superchijekwu
6 years ago
I love this question
wendy2cute
6 years ago
datz easy
Santosky
1 year ago
Nice one guyz
Lawal Olanrewaju
6 years ago
I follow u emekks
Shozlee
5 years ago
I love this
Tosihnodorcas
5 years ago
D ans is 2:3

f=ma

f1=m1a1=3*2=6

f2=m2a2=1*9=9

f1:f2=6:9=2:3
Ndukechrist
3 years ago
f1=m1*a1=3*2=6, f2=m2*a2=1*9=9, =6:9, divide through be 3 (smallest integer) ansa=2:3. ansa x c
krypton435
2 years ago
2:3
krypton435
2 years ago
i belive it has already been explained
eddino
6 years ago
Nice work guys
Esuo25
6 years ago
i'm proud of my gud students

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