### Two bodies have masses in the ratio 3:1. They experience forces which impart to them...

Two bodies have masses in the ratio 3:1. They experience forces which impart to them acceleration in the ratio 2:9 respectively. Find the ratio of forces the masses experienced.

• A. 1 : 4
• B. 2 : 1
• C. 2 : 3
• D. 2 : 5
##### Explanation

Let the forces be F1, and F2.
F1 = m1 a1 = 3 x 2 = 6N

F2 = m2 a2 = 1 x 9 = 9N

F1 : F2 = 6:9 = 2:3

Thus ratio of forces is 2: 3

#### Contributions (74)

Deducing d mathematical representation of Newton's 2nd law of motion,we have F=MA.Frm our quesn

M1=2,A1=3,M2=9,A2=1

Relate them 2gether:

2*3:9*1

=6:9(divide through using their possible smallest integers i.e3 ofcourse)

=2:3 ans.....c
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• Favour: Yea i undastand dis method
1 year ago
• EMMANUEL: yes
7 months ago
• Ebube: i like dis method it is simpler dis way
6 months ago
•      3 months ago
• Ebuka fulfill: Thanks 4 enlightening me more bro
3 weeks ago
Anoda method is,2:1and3:9=3/2*1/9,cross divide,which is 9 divided 3, u get 3,and 2 divided 1 u get 2,which is 2:3,as answer.
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Emekks tanks alot nd many of u guys 4 ur explalation ok am pleasured by it
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we know that f=ma and we are having 2 masses and 2 accelerarions....xo we jst say f1 * m1 = f2 * m2 which is equal "6=9"...then divide both sides with 3 den we have 2:3
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I love this question
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datz easy
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Nice one guyz
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I follow u emekks
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I love this
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D ans is 2:3

f=ma

f1=m1a1=3*2=6

f2=m2a2=1*9=9

f1:f2=6:9=2:3
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f1=m1*a1=3*2=6, f2=m2*a2=1*9=9, =6:9, divide through be 3 (smallest integer) ansa=2:3. ansa x c
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2:3
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i belive it has already been explained
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Nice work guys
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i'm proud of my gud students
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