Two resistors R1 and R2 are connected in parallel, R2 being greater than R1. The combined resistance is

teebreezy101

7 years ago

What is this now??? Resistors in parallel.. Effective resistance is 1/R=1/r+1/r hence A is the answer pleaseeee

Sammyporsche123

2 years ago

e connected in parallel, the combined resistance is given by the formula:
1/R​=1/R1​+1/R2​
This results in a resistance that is less than the smallest individual resistor. So, if R2 is greater than R1, the combined resistance will be less than R1. This is because the parallel connection provides multiple paths for the current to flow, effectively reducing the total resistance.

owuapu

5 years ago

i don't understand

efeoluwa

2 months ago

the answer is b since the question is asking for the combined resistance

Patrick28

3 years ago

A is correct

Sammyporsche123

3 years ago

The answer is B do the maths well

Ugbedeojo001

4 years ago

the correct answer is C, you simply add up resistance in parallel

Henry777

4 years ago

option E

Babliwa

3 years ago

The correct answer is E) greater than R1 but less than R2.

When two resistors are connected in parallel, the total resistance decreases. The combined resistance can be calculated using the following formula:

1/total resistance = 1/R1 + 1/R2

Rearranging this formula gives:

total resistance = R1R2 / (R1 + R2)

Since R2 is greater than R1, the denominator R1 + R2 is greater than R1 alone but less than R2 alone. Therefore, the total resistance is greater than R1 but less than R2.

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