A solid suspended by a piece of string is completely immersed in water. On attempting to lift the solid out of the water, the string breaks when the solid is partly out of the water. This is because
the tension in the string decreases as the solid is lifted
the mass of the solid has increased
the solid apparently weighs less when completely immersed in water than when partially immersed
part of the solid still in water is exerting more force on the string
the solid is no longer in equilibrium with water
Explanation
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This is because object are lighter when completely immersed in water compared to partially immersed in water
The correct answer is:
C. The solid apparently weighs less when completely immersed in water than when partially immersed.
Explanation:
When the solid is completely immersed in water, it experiences an upthrust (buoyant force) equal to the weight of the water it displaces. This reduces the apparent weight of the object, meaning the tension in the string is lower.
However, when the solid is partly lifted out of the water, the buoyant force decreases because less of the object is submerged, so the apparent weight increases. This increase in tension on the string causes it to break if the weight exceeds the string's limit.
Why the Other Options Are Incorrect:
A. The tension in the string decreases as the solid is lifted – Incorrect. The tension actually increases as the object is lifted out because the buoyant force decreases.
B. The mass of the solid has increased – Incorrect. The mass of the object remains constant; only the buoyant force changes.
D. Part of the solid still in water is exerting more force on the string – Incorrect. The force on the string comes from the object's weight, which increases as less of it is submerged.
E. The solid is no longer in equilibrium with water – Incorrect. Equilibrium is not the main reason for the string breaking; it's the loss of buoyant force.
