An air bubble rises from the bottom to the top of a water dam which is 40m deep. The volume of the bubble just below the surface is 2.5cm3. Find its volume at the bottom of the dam, if atmospheric pressure is equivalent to 10m water
a
0.0cm3
b
2.0cm3
c
1.6cm3
d
0.625cm3
e
0.5cm3
Explanation
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Discussions (6)

Chinonyerem127
3 years ago
the pressure at the bottom of the dam =atmospheric pressure +the pressure due to depth
and the pressure at the surface of the water =atmospheric pressure
so from p1v1=p2v2
p1=10+40=50
v1=?
v2 (at surface)=2.5
p2=10
50*v1=2.5*10
50*v1=25
v1=25/50
v1=0.5

Wawaaaaaaaaaaaqa
2 years ago
p1 is = depth + atmospheric pressure. (40 +10) = 50
p2 = atmospheric pressure = 10
V1 = volume at the BUTTOM = ?
v2= volume below the surface = 2.5
using p1v1 = P2v2
50*x = 10*2.5
x = 10*2.5/50 = 0.5

judesteve
4 years ago
Please I don't understand the second step of the procedure.please explain that second formula for me

