In an electrolysis experiment, a cathode of mass 5g is found o weigh 5.01g after a current of 5A flows for 50 seconds. What is the electrochemical equivalent of the deposited substance?
a
0.00004g/C
b
0.00002g/C
c
0.02500g/C
d
0.05000g/C
e
0.00001g/C
Explanation
Correct Option
aVideo Explanation
No video available
Post your Contribution
Share:
Discussions (6)
Miguelbarth
5 years ago
well the answer is correct, but the solution is not clear,
Mass of depostied substance M=M2-M1= 5.01 - 5 = 0.01g
using the formular M = ZIT
M = Mass of depostied substance = 0.01g
Z = Electrochemical equivalent = X
I = Current that flowed through the cathode = 5A
T = Time taken to conclude the experiment = 50sec
making Z subject of formular we have
Z = M/(IT)
Z = 0.01/(5*50)=0.01/250
Z = 0.00004g/C
