The bulb of a motorcycle head-lamp is marked 40W, 6V. The resistance of the filament when it is switched on is

a

\(\frac{6^2}{40^2}\)ohms

b

\(\frac{40}{6^2}\)ohms

c

\(\frac{40}{6}\)ohms

d

6 x 40 ohms

e

\(\frac{6^2}{40}\)ohms

Download Offline App Ask a Question

Explanation

Correct Option
e

Video Explanation

No video available

Post your Contribution

Share:

Discussions (4)

Chi4sure
2 years ago

P=IV
I=V/R
P= V/R×V
P=V×V/R
R=V×V/P
R=V^2/P

Anela
3 months ago

P=V²/R

P=40
V=6
r=?

40=6²/R

cross multiply ❌
40R=6²
DBS by 40

R=6²/40

Danvielson
1 year ago

I need to connect with anyone who is aspiring to study medicine and surgery in either UNIBADAN or UNIABUJA🙏🙏🙏. I need a study partner.

Quick Questions

Ask a Question
CO

ceoofwahala

20th June, 2026

Chemistry


2 comments

ASSAAS

20th June, 2026

English Language


5 comments

infinitehoaxx

21st May, 2026

Computer


4 comments