An electric cell has an internal resistance of 2 ohms. A current of 0.5A is found to flow when a resistor of 5 ohms resistance is connected across it. What is the electromotive force of the cell?

Iamenoch

2 years ago

Yes! the answer is b
E=IR+Ir
internal resistance (r)=2ohms
current (I)=0.5A
external resistance,(R)=5ohms
applying the formula...
E=0.5(5)+0.5(2)
E=1/2×5+1/2×2
E=2.5+1
E=3.5volts
remember to always out your unit...

blessingsilas98

1 year ago

the question isnt correct

Anela

3 months ago

E=I(R+r)

E=?
I=0.5
r=2
R=5
(r+R)=5+2= 7

;E=0.5×7
= 3.5

MMDanliti

2 months ago

i disnt understand nothing