Physics
JAMB 1979
A 500kg car which was initially at rest travelled with an acceleration of 5m sec
-2, its kinetic energy after 4 seconds was
-
A.
105J
-
B.
2.5 x 103J
-
C.
2 x 103J
-
D.
5 x 103J
-
E.
5 x 105J`
Correct Answer: Option A
Explanation
K.E = \(\frac{1}{2}\)mv2; m (at + u)2
since, v = at + u = \(\frac{1}{2}\) x 500 [(5 x 4)+ 0]2
= 105J
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