What is the relative permitivity of a capacitor if its capacitance with a medium as dielectric is 16 farads and its capacitance with vacuum as dielectric is 2 farads?

Iyandadaniel

5 years ago

You can use another formular.capacitance=dielectric of vaccum/dielectric in medium=2/16=0.125.permitivity=1/capacitance.therefore,1/0.125=8.

Efranklyn

4 years ago

We know that the capacitance is given by
C = EA(n-1)/d -------- capacitance in a material of permittivity E
Co = EoA(n-1)/d -------- capacitance in a free space or vaccum
Substituting terms in eqn(1) and eqn(2)
Co = Eo(C/E) -----------(3)
But we know that the relative permittivity is given by
E = Er×Eo
Er = E/Eo-----------(4)
Substituting eqn 4 into 3
Co = C/Er
where
Er = C/Co
The answer is D

qazeemmayowa123

9 years ago

Very wrong

Er=Eo x E

Er=2x16=32