What is the relative permitivity of a capacitor if its capacitance with a medium as dielectric is 16 farads and its capacitance with vacuum as dielectric is 2 farads?
a
o
b
\(\frac{1}{2}\)
c
2
d
8
e
32
Explanation
Correct Option
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Discussions (7)
Iyandadaniel
5 years ago
You can use another formular.capacitance=dielectric of vaccum/dielectric in medium=2/16=0.125.permitivity=1/capacitance.therefore,1/0.125=8.
Efranklyn
4 years ago
We know that the capacitance is given by
C = EA(n-1)/d -------- capacitance in a material of permittivity E
Co = EoA(n-1)/d -------- capacitance in a free space or vaccum
Substituting terms in eqn(1) and eqn(2)
Co = Eo(C/E) -----------(3)
But we know that the relative permittivity is given by
E = Er×Eo
Er = E/Eo-----------(4)
Substituting eqn 4 into 3
Co = C/Er
where
Er = C/Co
The answer is D
