A solid weighs 4.8g in air, 2.8g in water and 3.2g in kerosine. The ratio of density of the solid to that of the kerosine is
a
12
b
3
c
2
d
\(\frac{3}{2}\)
e
\(\frac{5}{4}\)
Explanation
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Discussions (10)
Animashaunfemi
1 year ago
okay just do it like this.
use the density of the object in air straight.
but first get your density of solid in kerosine first. like this RD=4.8-3.2=1.6.
then you get the raitio of density of solid in air and in kerosene, by. Ratio of Da(air)/Dk(kerosene)= 4.8/1.6=3 this is easier.
AmaraChris
1 year ago
how did you calculate for the "equal volume of water" in both cases i.e for relative density of both the solid and the liquid
