Two particles X and Y starting from rest cover the same distance. The acceleration of X is twice that of Y. the ratio of the time taken by X to that taken by Y is
\(\frac{1}{2}\)
\(\frac{2}{\sqrt2}\)
\(\frac{1}{\sqrt2}\)
\(\sqrt 2\)
4
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Discussions (26)
S =ut +1/2 at^2
but u=0
s=1/2at^2
x. y
s=1/2ax(tx)^2. s=1/2ay(ty)^2
but they have same distance also u clear the fraction by multiplying 2 in each term
ax(tx)^2. ay(ty)^2
divide x by y
ax/ay =(ty/tx)^2
but x=2y(for acceleration)
which is also a=2a where a is for x and 2a is for y
a/2a=(ty/tx)^2
1/2 =(ty/tx)^2
tx/ty=√1 /√2
=1/√2
The answer is D. The question says ratio of the time of x to y, not the other way round
the equations and formulas are written unclearly as only a coder can understand them.
