0m to 0.1m
0m to 0.25m
0.10m to 0.25m
0.10m to infinity
0.25m to infinity
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Discussions (4)
The correct answer is:
E. 0.25 m to infinity
For a normal human eye:
The least distance of distinct vision (near point) is 0.25 m (25 cm)
The far point is at infinity
The range of accommodation is therefore from 25 cm to infinity.
That means:
The eye can clearly see objects as close as 0.25 m
And as far as very distant objects (∞)
Why others are wrong:
A & B (0 m …) → 0 m is impossible; no object can be seen at zero distance.
C (0.10 m to 0.25 m) → 10 cm is too close for a normal eye.
D (0.10 m to ∞) → 10 cm is not the standard near point for a normal eye.
For JAMB revision, just lock this in:
Near point = 25 cm
Far point = Infinity
Range = 0.25 m to ∞
