Physics
JAMB 1982
250g of lead at 170
oC is dropped into 100g of water at 0
oC. If the final temperature is 12
oC, the specific heat of lead is (specific heat of water is 4,200J/kg
oC)
-
A.
39.5J/kgoC
-
B.
50.4J/kgoC
-
C.
127.6J/kgoC
-
D.
154.6J/kgoC
-
E.
173.4J/kgoC
Correct Answer: Option C
Explanation
Heat lost = heat gained
0.25 x C1 x (170 - 12) = 0.1 x 4200 x (12 - 0)
C1 = 127.6J/kgoC
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}