The tyre pressure of a car was found to be 150cmHg in the morning at a temperature of 27°C. Hard driving in the afternoon raised the temperature of the tyres to 57°C. The tyre pressure had by the afternoon was?
\(\frac{P_1}{T_1}\) = \(\frac{P_2}{T_2}\) at constant volume
\(\frac{150}{27 + 273}\) = \(\frac{P_1}{57 + 273}\)
P2 = 165cmHg
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