Physics
JAMB 1982
The hatch door of a submarine has an area of 0.5m
2. The specific gravity of sea water is 1.03. Assume that g = 10ms
-1,and neglect the atmospheric pressure. The force exerted by the sea water on the hatch door at a depth of 200m is
-
A.
1.03 x 105N
-
B.
1.03 x 104Nm-2
-
C.
1.06 x 105Nm-2
-
D.
2.06 x 106N
-
E.
1.03 x 103N
Correct Answer: Option E
Explanation
Pressure in liquid = e x h x g
Pressure in solid = \(\frac{force}{area}\)
\(\frac{force}{area}\) = e x h x g
force = 0.5 x 10 x 200 x 1.03
= 1030N
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