The hatch door of a submarine has an area of 0.5m2. The specific gravity of sea water is 1.03. Assume that g = 10ms-1,and neglect the atmospheric pressure. The force exerted by the sea water on the hatch door at a depth of 200m is
a
1.03 x 105N
b
1.03 x 104Nm-2
c
1.06 x 105Nm-2
d
2.06 x 106N
e
1.03 x 103N
Explanation
Correct Option
eVideo Explanation
No video available
Post your Contribution
Share:
Discussions (8)
Super01
10 years ago
Specific gravity also means relative density. So the density of sea water =(1.03×1000),therefore the answer is A.
1.03 can't be used directly because it is the relative density and not the direct density of sea water.
#Stand to be corrected
