a force of 16N applied 4.0kg block that is at rest on a smooth, horizontal surface. What is the velocity of the block at t = 5 seconds?

Corne26

3 years ago

using the equation of motion, v = u + at ,where t is = 5 seconds u = 0.

But a is not given, so how can we find our a, which is the acceleration

force = mass * acceleration, so where our force is 16N our mass is 4.0kg

Now to find our acceleration , which is not given , we can use acceleration as

the subject of the formular,i.e a = force/mass,

a = 16/4 = 4 , so our acceleration equals 4

So the first equation of motion equals v = u + at
v = 0 + 4 * 5
v = 0 + 20
v = 20 option C

mmeso736

1 year ago

beautiful 😍❤️

BlowBubblegum

2 years ago

To determine the velocity of the block at t = 5 seconds, we need to apply Newton's second law of motion.

Given:
Force applied (F) = 16 N
Mass of the block (m) = 4.0 kg
Time (t) = 5 seconds

According to Newton's second law, the acceleration of an object is equal to the net force acting on it divided by its mass:

a = F / m

Substituting the given values, we have:

a = 16 N / 4.0 kg
a = 4.0 m/s^2

Since the block is initially at rest, its initial velocity (u) is 0 m/s. We can use the equation of motion to find the final velocity (v) at time t:

v = u + a * t

Substituting the values, we get:

v = 0 m/s + (4.0 m/s^2) * 5 s
v = 20 m/s

Therefore, the velocity of the block at t = 5 seconds is 20 m/s. The correct answer is C. 20m/s.