Physics
JAMB 1983
A milliameter with full scale deflection of 10mA has an internal resistance of 5 ohms. It would be converted to an ammeter with a full scale deflection of 1A by connecting a resistance of
-
A.
\(\frac{5}{99}\)ohms in series with it
-
B.
\(\frac{5}{99}\)ohms in parallel with it
-
C.
\(\frac{99}{5}\)ohms in series with it
-
D.
\(\frac{99}{5}\)ohms in parallel with it
-
E.
2 ohms in series with it
Correct Answer: Option B
Explanation
I = 1 - (10 x 10-3)
= 0.99A
IR = 10 x 10 x 10-3 x 5
R = \(\frac{5}{99}\)\(\Omega\)
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}