If the pressure on 100cm3 of an ideal gas is doubled while its kelvin temperature is halved, then the new volume of the gas will become
25cm3
50cm3
100cm3
200cm3
400cm3
Explanation
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Discussions (19)

all of a sudden you guys introduced 1000 in your answers,thought what you gave in the question was 100? This kind thing tire me o

dear ladies and gentlemen
when solving this like this ...to avoid getting urself confused input Ur own numbers
example
v1= 100
p1 = remember they said pressure is doubled...you can just decide to make p1 = 10. then double P2(20)
T1= remember they said temperature is halved...you can also decide to make T1 = 10k then halved it in T2(5k)
now
v2=?
P2= remember it should be double of p1 which is 20
T2= remember it should be halved of T1 which is 5
now let's recap:
V1= 100
P1= 10
T1= 10
V2= ?
P2= 20
T2= 5
solve this using Ur formula (P1v1÷T1 = P2v2÷T2). you definitely get the same answer
thank you.

your solution is very wrong...my school,why are u guys fumbling,I thought your app was the best,omor I'm regretting oh


