If relative density of a metal is 19, what will be the mass of 20cm3 of the metal when immersed in water?

Gbolly4d44

4 years ago

Please note that the answer here is wrong...

Rd(m)=19, d(m)=19g/cm³
V=20cm³=volume of water displaced
Lq-M(m)=d×V=19×20=380=mass of metal in air
But,U=Wa-Wl=dVg or Ma-Mw=dwVw

380-Mw=1×20, 380-Mw=20

Mw=380-20=360g
Which leaves option C correct 💯


Autodidactic-gbolly 💯🔥💯

CRIMHAZ

3 years ago

THE ANS IS OBVIOUSLY A

Because

When objects are placed in water, their mass does not change. They seem to feel lighter, though, because of buoyancy. Archemedes's principle states that the force pushing on an object under water, is equal to the mass of the water it has pushed out of the way.

Alechpeter

7 years ago

Please is this a post utme past question or jamb?

Abdullahi113

1 year ago

use the formula Density = mass / volume. p = m/v

OwoukoUrua

7 years ago

Mass = 380g . . . Apparent mass when immersed in water = 360g

EPHRAIMWILSON

11 months ago

The explanation to the answer is wrong particularly the formula
it suppose to be Mass = relative density * equal volume of water not velocity.

smartgenius

1 year ago

velocity or volume 😑😑😑😑

topeter997

10 years ago

360g is the answer......first of all find the mass in air

after use this to get ur final answer R.D=weight in air/wt in air - wt in water

weight=Mg......cancel 'g'

Mg/Mg air - Mg water

R.d=g[M]/g[M air - M water]

R.d=M air/M air - M water