In a resonance tube experiment, a tube fixed length is closed at one end and several tuning forks of increasing frequency used to obtain resonance at the open end. If the tuning fork with the lowest frequency which gave resonance had a frequency f1 and the next tuning fork to give resonance had a frequency f2, find the ratio \(\frac{f^2}{f^1}\).

a

8

b

3

c

2

d

\(\frac{1}{2}\)

e

\(\frac{1}{3}\)

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b

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Discussions (11)

f1=1v/4l
f2=3v/4l
f2/f1=(3v/4l)÷1v/4l
=(3v/4l)×(4l/1v)
=3/1
=3:1

FRESCID
5 years ago

You wrote f² / f² instead of the f2 /f1 you did write in your explanation.

Godsfavour09
2 years ago

/(/frac{1}{2}\)

kairakizitor7
1 year ago

just dey play 😂

OsagieN
3 years ago

𝐁✅✅.

Ebenezer1100
1 year ago

F²/F²?

omopariolaSamuel
7 years ago

i really don't think this is correct.it should be 2
since f1=v/4L
F2=V/2L
F2/F1=2

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