Physics
JAMB 1984
A particle moves in a circular orbit of radius 0.02m. If the speed of the particle is 0.88ms
-1, calculate its frequency in cycles per second
-
A.
2.0Hz
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B.
7.0Hz
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C.
8.8Hz
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D.
14.0Hz
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E.
17.6Hz
Correct Answer: Option B
Explanation
W = \(\frac{v}{r}\)
= \(\frac{0.88}{0.02}\) = 44 rad/s
2\(\pi\)F = W = 44
F = \(\frac{44}{2 \times 3.142}\)
= 7Hz
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