A body of mass 5kg initially at rest is acted upon by two mutually perpendicular forces 12N and 5N as shown in fig.3. If the particle moves in the direction QA, calculate the magnitude of the acceleration
a
0.40ms-2
b
1.40ms-2
c
0.26ms-2
d
2.60ms-2
e
3.40ms-2
Explanation
Correct Option
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Blesseddivine
4 months ago
Easiest way to solve....
R²=(F1)²+(F2)²
=12²+5²
=144+25
=169
R=√169
=13..
Magnitude=13/5
=2.60....
Abdullahi113
1 year ago
My school please find something to do to it oooo there is no diagram as illustrated in the questions
