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Two cells each of e.m.f. 1.5V and an internal resistance 2\(\Omega\) are connected in parallel....

Physics
JAMB 1984

Two cells each of e.m.f. 1.5V and an internal resistance 2\(\Omega\) are connected in parallel. Calculate the current flowing when the cells are connected to a 1\(\Omega\) resistor
  • A. 0.75\(\Omega\)
  • B. 1.5\(\Omega\)
  • C. 0.5\(\Omega\)
  • D. 1.0\(\Omega\)
  • E. 0.6\(\Omega\)
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Correct Answer: Option A
Explanation
E = 1.5v

rT = \(\frac{2 \times 2}{2 + 2}\)
= 1

e.m.f. = I(R + r)

1.5 = I(1 + 1)

I = 0.75\(\Omega\)

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JAMB CBT Software 2025 - Free Download
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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 127076
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