The distance travelled by a particle starting from rest is plotted against the square of the time elapsed from the commencement of motion. The resulting graph is linear, the slope of this graph is a measure of
The slope of the graph of distance versus time squared is equal to \(\frac{1}{2}\)a, which means the slope measures half the acceleration.
Also from s = ut + \(\frac{1}{2}\)at\(^2\)
when u = 0 then, s = \(\frac{1}{2}\)at\(^2\)
So, \(\frac{Δ\text{s}}{Δt^2}\) = \(\frac{1}{2}\)a
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