Two rays of light from a point below the surface of water are equally inclined to each other at 60o in water. What is the angle between the rays when they emerge into air? (Take the refractive index of water to be \(\frac{4}{3}\))

a

41.8o

b

44.1o

c

60.0o

d

83.6o

e

120.0o

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Correct Option
d

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Discussions (19)

Immatiti
4 years ago

where is sin 30 coming from

Mickey2.0
3 years ago

Snell's law is n= sin i/sin r and not the other way round. So the answer is B

Dave333
4 years ago

So we are going to add the both🤦🙍

FavourAlo
9 years ago

How did we get 41.8?

Knowledge_OA
2 years ago

Option D✅

FAECSB7610542
1 year ago

I guess we're going to learn the whole trigonometry from sin 1 to 360 and even do so for cos and tan 😂, coz how do you expect us to solve this men?¡¡.

afolabifaith777
2 months ago

And which calculator are we going to use to solve this?

Elite_kid23
1 year ago

hmmmmmm God go help us

Rizuko_Chan
1 year ago

Does anyone have an easier way to solve this?...

hey the formula sef is incorrect it is sin I/ sin r not r / I check back

RALPHAEL
2 months ago

dont understand

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