Two thermo flasks of volume Vx and Vy are filled with liquid water at an initial temperature of 0oC. After sometime the temperature were found to be 9x, 9y, respectively. Given that \(\frac{Vx}{Vy}\) = 2 and \(\frac{\theta x}{\theta y}\) = \(\frac{1}{2}\) the ratio of the heat flow into the flask is
\(\frac{1}{4}\)
\(\frac{1}{2}\)
4
1
2
Explanation
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Discussions (7)
This is a simple logic, no need for long solutions.
Since we know both liquids are water, c is constant.
Therefore H is directly proportional to M×t(temperature)
For non-gases, mass is generally directly proportional to volume.
This means H is dir. prop. to V
This is a simple logic, no need for long solutions.
Since we know both liquids are water, c is constant.
Therefore H is directly proportional to M×t(temperature)
For non-gases, mass(M) is generally directly proportional to volume(V).
This means H is dir. prop. to Vt
Hx/Hy=Vxty/Vxty
We can then see it's simply 2/2=1
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