Physics
JAMB 1985
Two liquids, P at a temperature of 20
oC and Q at a temperature of 80
oC have specific heat capacities of 1.0Jkg
-1oC
-1 and 1.5J kg
-1 oC
-1respectively. if equal masses of P and Q are mixed in a lagged calorimeter, then the equilibrium temperature is
-
A.
44oC
-
B.
50oC
-
C.
56oC
-
D.
60oC
-
E.
70oC
Correct Answer: Option C
Explanation
Heat lost = heat gained
m x (80 - \(\theta\)) x 1.5 = m x (\(\theta\) - 20) x 1
\(\theta\) = 56oC
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