A uniform cylindrical block of wood floats in water with one-third of its height above the water level, in a liquid of relative density 0.8, what fraction of its height will be above the liquid level?

a

\(\frac{1}{6}\)

b

\(\frac{1}{5}\)

c

\(\frac{1}{3}\)

d

\(\frac{4}{5}\)

e

\(\frac{5}{6}\)

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a

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Discussions (24)

ayorinde01
5 years ago
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The answer is 1/6
Use this solution πŸ‘‡πŸ‘‡

agadido
3 years ago

Myschool its not by force to manipulate.
U asked for the height above the liquid not the height inside the liquid, Kelly whats ut problemπŸ™β˜ΉοΈπŸ˜•

Dave333
4 years ago

This is how they got 2/3
Height below liquid=1-1/3
3-1/3=2/3πŸ™‚

Femimartinz
2 years ago

Pls the solution

neemah10
5 months ago

the explanation is not clear enough

authority108
11 years ago

I think R.D=height in liquid/height in water

BlessedDrNuel
10 years ago

The options are not there

agadido
3 years ago

U asked for the height above the liquid then that is obviously 1/6 not 5/6 what u are finding is height in the liquid

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