Two divers G and H are at depths 20m and 40m respectively below the water surface in a lake. The pressure on G is P1 while the pressure on H is P2. If the atmospheric pressure is equivalent to 10m of water, then the value of \( \frac{p_2}{p_1} \) is?
pressure at H = 40m ; pressure at G, p1 = 20m
\(\frac{p_1}{p_1}\) = \(\frac{40 + 10}{20 + 10}\)
= \(\frac{50}{30}\)
≈ 1.67
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}